8x=(6x)^2

Solution for 8x=(6x)^2 equation:

8x=(6x)^2

We move all terms to the left:

8x-((6x)^2)=0

determiningTheFunctionDomain
8x-6x^2=0

We add all the numbers together, and all the variables

-6x^2+8x=0

a = -6; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-6)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-6}=\frac{-16}{-12}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-6}=\frac{0}{-12}
=0
$